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导数题 1

Easy Differentiate 1

专题
General / 综合
难度
L4

题目详情

求导:f(x)=xlog(x)f(x)=x\log(x)

英文原题

Differentiate f(x)=xlog(x)f(x) = x \log (x) .

解析

默认 log\log 为自然对数。用乘积法则:

ddx[xlogx]=1logx+x1x=logx+1.\frac{d}{dx}[x\log x]=1\cdot\log x + x\cdot\frac1x = \log x+1.

因此

f(x)=logx+1.\boxed{f'(x)=\log x+1}.

英文解析

By default, log\log denotes the natural logarithm. Using the product rule:

ddx[xlogx]=1logx+x1x=logx+1.\frac{d}{dx}[x\log x]=1\cdot\log x + x\cdot\frac1x = \log x+1.

Therefore

f(x)=logx+1.\boxed{f'(x)=\log x+1}.