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关于 0TW(t)dt\int_0^T W(t)dt

Stochastic calculus for brownian

专题
Finance / 金融
难度
L4

题目详情

How fresh is your stochastic calculus? What can you tell me about 0Tw(t)dt\int_{0}^{T}w(t)dt , where w(t)w(t) is a standard Brownian motion?

解析

W(t)W(t) 路径几乎处处连续,因此 0TW(t)dt\int_0^T W(t)dt 是逐路径的 Riemann 积分。

它是正态随机变量,且可用积分分部把它写成 Itô 积分:

0TW(t)dt=0T(Ts)dWs.\int_0^T W(t)dt=\int_0^T (T-s)\,dW_s.

因此

E[0TW(t)dt]=0,\boxed{\mathbb{E}\left[\int_0^T W(t)dt\right]=0}, Var(0TW(t)dt)=0T(Ts)2ds=T33.\boxed{\operatorname{Var}\left(\int_0^T W(t)dt\right)=\int_0^T (T-s)^2ds=\frac{T^3}{3}}.