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波动率趋于无穷:call 价格极限

Vanilla call option

专题
Finance / 金融
难度
L4

题目详情

What happens to the price of a vanilla call option as volatility tends to infinity?

解析

在 Black–Scholes(无分红 q=0q=0)下

C=S0N(d1)KerTN(d2),d1=ln(S0/K)+(r+12σ2)TσT, d2=d1σT.C=S_0N(d_1)-Ke^{-rT}N(d_2),\quad d_1=\frac{\ln(S_0/K)+(r+\frac12\sigma^2)T}{\sigma\sqrt{T}},\ d_2=d_1-\sigma\sqrt{T}.

σ\sigma\to\infty 时,d1+d_1\to +\inftyd2d_2\to -\infty,所以 N(d1)1N(d_1)\to 1N(d2)0N(d_2)\to 0,从而

limσC=S0\boxed{\lim_{\sigma\to\infty} C = S_0}

(若有分红率 qq,则极限为 S0eqTS_0e^{-qT})。