平值、r = 0 r=0 r = 0 、无分红时,短期限 Black-Scholes 近似为
P A T M ≈ S σ T 2 π ≈ 0.4 S σ T . P_{ATM}\approx \frac{S\sigma\sqrt{T}}{\sqrt{2\pi}}\approx 0.4S\sigma\sqrt{T}. P A T M ≈ 2 π S σ T ≈ 0.4 S σ T .
本题 S = K = 40 S=K=40 S = K = 40 ,σ = 0.30 \sigma=0.30 σ = 0.30 ,T = 1 / 4 T=1/4 T = 1/4 ,所以
P ≈ 0.4 ⋅ 40 ⋅ 0.30 ⋅ 1 2 = 2.40. P\approx 0.4\cdot 40\cdot 0.30\cdot \frac12=2.40. P ≈ 0.4 ⋅ 40 ⋅ 0.30 ⋅ 2 1 = 2.40.
若用精确 Black-Scholes 公式,
d 1 = 0.075 , d 2 = − 0.075 , P = 40 ( N ( 0.075 ) − N ( − 0.075 ) ) ≈ 2.39. d_1=0.075,\quad d_2=-0.075,\quad
P=40\bigl(N(0.075)-N(-0.075)\bigr)\approx 2.39. d 1 = 0.075 , d 2 = − 0.075 , P = 40 ( N ( 0.075 ) − N ( − 0.075 ) ) ≈ 2.39.
因此该 put 约值 2.4 \boxed{2.4} 2.4 。
英文解析
For an at-the-money option with r = 0 r=0 r = 0 and no dividends, the short-maturity Black-Scholes approximation is
P A T M ≈ S σ T 2 π ≈ 0.4 S σ T . P_{ATM}\approx \frac{S\sigma\sqrt{T}}{\sqrt{2\pi}}\approx 0.4S\sigma\sqrt{T}. P A T M ≈ 2 π S σ T ≈ 0.4 S σ T .
Here S = K = 40 S=K=40 S = K = 40 , σ = 0.30 \sigma=0.30 σ = 0.30 , and T = 1 / 4 T=1/4 T = 1/4 , so
P ≈ 0.4 ⋅ 40 ⋅ 0.30 ⋅ 1 2 = 2.40. P\approx 0.4\cdot 40\cdot 0.30\cdot \frac12=2.40. P ≈ 0.4 ⋅ 40 ⋅ 0.30 ⋅ 2 1 = 2.40.
Using the exact Black-Scholes formula gives
d 1 = 0.075 , d 2 = − 0.075 , P = 40 ( N ( 0.075 ) − N ( − 0.075 ) ) ≈ 2.39. d_1=0.075,\quad d_2=-0.075,\quad
P=40\bigl(N(0.075)-N(-0.075)\bigr)\approx 2.39. d 1 = 0.075 , d 2 = − 0.075 , P = 40 ( N ( 0.075 ) − N ( − 0.075 ) ) ≈ 2.39.
So the put is worth about 2.4 \boxed{2.4} 2.4 .