HMMT 十一月 2010 · 冲刺赛 · 第 25 题
HMMT November 2010 — Guts Round — Problem 25
题目详情
英文原题
- [ 14 ] Triangle ABC is given with AB = 13, BC = 14, CA = 15. Let E and F be the feet of thealtitudes from B and C , respectively. Let G be the foot of the altitude from A in triangle AF E . Find
AG .
解析
英文解析
- [ 14 ] Triangle ABC is given with AB = 13, BC = 14, CA = 15. Let E and F be the feet of thealtitudes from B and C , respectively. Let G be the foot of the altitude from A in triangle AF E . Find
AG .
√
Answer: By Heron’s formula we have [ ABC ] = 21(8)(7)(6) = 84. Let D be the foot of the 396
8465
altitude from A to BC ; then AD = 2 · = 12. Notice that because ∠ BF C = ∠ BEC , BF EC iscyclic, so ∠ AF E = 90 − ∠ EF C = 90 − ∠ EBC = ∠ C . Therefore, we have 4 AEF ∼ 4 ABC , so 14
√
√
( )
2 2 2
AG AE 1 56 56 65 − 56 33 = ; ( BE )( AC ) = 84 = ⇒ BE = = ⇒ AE = 13 − = = . Then 2
AD AB 2 5 5 5 52
33 / 5
AE 396
AG = AD · = 12 · = .
AB 13 65