HMMT 十一月 2010 · 冲刺赛 · 第 24 题
HMMT November 2010 — Guts Round — Problem 24
题目详情
英文原题
- [ 12 ] Let P ( x ) be a polynomial of degree at most 3 such that P ( x ) = for x = 1 , 2 , 3 , 4. What is
1+ x + x 2
P (5)?
解析
英文解析
- [ 12 ] Let P ( x ) be a polynomial of degree at most 3 such that P ( x ) = for x = 1 , 2 , 3 , 4. What is
1+ x + x 2
P (5)?
Guts Round − 3
Answer: The forward difference of a polynomial P is ∆ P ( x ) = P ( x + 1) − P ( x ), which is a newpolynomial with degree reduced by one. Therefore, if we apply this operation three times we’ll get a 91
constant function, and we can work back up to get a value of P (5). Practically, we create the followingtable of differences:
1 1 1 1
3 7 13 21 − 4 − 6 − 8
21 91 273
34 10
273 273 − 24
Then extend it to be the following table:273
1 1 1 1 − 9
3 7 13 21 273 − 4 − 6 − 8 − 22
21 91 273 273
34 10 − 14
273 273 273 − 24 − 24
273 273 − 9 − 3
So our answer is =
273 91