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HMMT 十一月 2010 · 冲刺赛 · 第 26 题

HMMT November 2010 — Guts Round — Problem 26

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 14 ] w, x, y, z are real numbers such thatw + x + y + z = 5
    2 w + 4 x + 8 y + 16 z = 7
    3 w + 9 x + 27 y + 81 z = 11
    4 w + 16 x + 64 y + 256 z = 1
    What is the value of 5 w + 25 x + 125 y + 625 z ?
    2 2010
解析

英文解析

  1. [ 14 ] w, x, y, z are real numbers such thatw + x + y + z = 5
    2 w + 4 x + 8 y + 16 z = 7
    3 w + 9 x + 27 y + 81 z = 11
    4 w + 16 x + 64 y + 256 z = 1
    What is the value of 5 w + 25 x + 125 y + 625 z ?
    Answer: − 60 We note this system of equations is equivalent to evaluating the polynomial (in a )
    2 3 4
    P ( a ) = wa + xa + ya + za at 1, 2, 3, and 4. We know that P (0) = 0, P (1) = 5, P (2) = 7, P (3) = 11,
    P (4) = 1. The finite difference of a polynomial f is f ( n + 1) − f ( n ), which is a polynomial withdegree one less than the degree of f . The second, third, etc finite differences come from applying thisoperation repeatedly. The fourth finite difference of this polynomial is constant because this is a fourthdegree polynomial. Repeatedly applying finite differences, we get
    0 5 7 11 1
    5 2 4 − 10 − 3 2 − 14
    5 − 16 − 21
    and we see that the fourth finite difference is − 21. We can extend this table, knowing that the fourthfinite difference is always -21, and we find that that P (5) = − 60. The complete table is
    Guts Round
    0 5 7 11 1 − 60
    5 2 4 − 10 − 61 − 3 2 − 14 − 51
    5 − 16 − 37 − 21 − 21
    2 2010