HMMT 十一月 2010 · 冲刺赛 · 第 26 题
HMMT November 2010 — Guts Round — Problem 26
题目详情
英文原题
- [ 14 ] w, x, y, z are real numbers such thatw + x + y + z = 5
2 w + 4 x + 8 y + 16 z = 7
3 w + 9 x + 27 y + 81 z = 11
4 w + 16 x + 64 y + 256 z = 1
What is the value of 5 w + 25 x + 125 y + 625 z ?
2 2010
解析
英文解析
- [ 14 ] w, x, y, z are real numbers such thatw + x + y + z = 5
2 w + 4 x + 8 y + 16 z = 7
3 w + 9 x + 27 y + 81 z = 11
4 w + 16 x + 64 y + 256 z = 1
What is the value of 5 w + 25 x + 125 y + 625 z ?
Answer: − 60 We note this system of equations is equivalent to evaluating the polynomial (in a )
2 3 4
P ( a ) = wa + xa + ya + za at 1, 2, 3, and 4. We know that P (0) = 0, P (1) = 5, P (2) = 7, P (3) = 11,
P (4) = 1. The finite difference of a polynomial f is f ( n + 1) − f ( n ), which is a polynomial withdegree one less than the degree of f . The second, third, etc finite differences come from applying thisoperation repeatedly. The fourth finite difference of this polynomial is constant because this is a fourthdegree polynomial. Repeatedly applying finite differences, we get
0 5 7 11 1
5 2 4 − 10 − 3 2 − 14
5 − 16 − 21
and we see that the fourth finite difference is − 21. We can extend this table, knowing that the fourthfinite difference is always -21, and we find that that P (5) = − 60. The complete table is
Guts Round
0 5 7 11 1 − 60
5 2 4 − 10 − 61 − 3 2 − 14 − 51
5 − 16 − 37 − 21 − 21
2 2010