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HMMT 二月 2006 · CALC 赛 · 第 4 题

HMMT February 2006 — CALC Round — Problem 4

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. Compute .
    k !
    k =1

    dx 1
解析

英文解析

  1. Compute .
    k !
    k =1
    Answer: 15 e
    Solution: Define, for non-negative integers n ,

    ∑nk
    S := ,
    k !nk =0
    where 0 = 1 when it occurs. Then S = e , and, for n ≥ 1,01
    ( )0
    ∞ ∞ ∞ ∞ n − 1
    n n n n − 1
    ∑ ∑ ∑ ∑ ∑
    k k ( k + 1) ( k + 1) n − 1
    S = = = = = S ,
    n ik ! k ! ( k + 1)! k ! ii =0
    k =0 k =1 k =0 k =0
    so we can compute inductively that S = e , S = 2 e , S = 5 e , and S = 15 e .
    1 2 3 4