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HMMT 二月 2006 · CALC 赛 · 第 3 题

HMMT February 2006 — CALC Round — Problem 3

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. At time 0, an ant is at (1 , 0) and a spider is at ( − 1 , 0). The ant starts walkingcounterclockwise along the unit circle, and the spider starts creeping to the right alongthe x -axis. It so happens that the ant’s horizontal speed is always half the spider’s.
    What will the shortest distance ever between the ant and the spider be?

    ∑4 k
解析

英文解析

  1. At time 0, an ant is at (1 , 0) and a spider is at ( − 1 , 0). The ant starts walkingcounterclockwise along the unit circle, and the spider starts creeping to the right alongthe x -axis. It so happens that the ant’s horizontal speed is always half the spider’s.
    What will the shortest distance ever between the ant and the spider be?

    Answer:14
    Solution: Picture an instant in time where the ant and spider have x -coordinates a 4
    and s , respectively. If 1 ≤ s ≤ 3, then a ≤ 0, and the distance between the bugs is atleast 1. If s > 3, then, needless to say the distance between the bugs is at least 2. If − 1 ≤ s ≤ 1, then s = 1 − 2 a , and the distance between the bugs is

    √2

    (8 a − 3) + 7
    2 2 2
    ( a − (1 − 2 a )) + (1 − a ) = 8 a − 6 a + 2 = ,
    √8
    which attains the minimum value of 7 / 8 when a = 3 / 8.

    ∑4 k