HMMT 二月 2006 · CALC 赛 · 第 3 题
HMMT February 2006 — CALC Round — Problem 3
题目详情
英文原题
- At time 0, an ant is at (1 , 0) and a spider is at ( − 1 , 0). The ant starts walkingcounterclockwise along the unit circle, and the spider starts creeping to the right alongthe x -axis. It so happens that the ant’s horizontal speed is always half the spider’s.
What will the shortest distance ever between the ant and the spider be?
∞
∑4 k
解析
英文解析
- At time 0, an ant is at (1 , 0) and a spider is at ( − 1 , 0). The ant starts walkingcounterclockwise along the unit circle, and the spider starts creeping to the right alongthe x -axis. It so happens that the ant’s horizontal speed is always half the spider’s.
What will the shortest distance ever between the ant and the spider be?
√
Answer:14
Solution: Picture an instant in time where the ant and spider have x -coordinates a 4
and s , respectively. If 1 ≤ s ≤ 3, then a ≤ 0, and the distance between the bugs is atleast 1. If s > 3, then, needless to say the distance between the bugs is at least 2. If − 1 ≤ s ≤ 1, then s = 1 − 2 a , and the distance between the bugs is
√
√2
√
(8 a − 3) + 7
2 2 2
( a − (1 − 2 a )) + (1 − a ) = 8 a − 6 a + 2 = ,
√8
which attains the minimum value of 7 / 8 when a = 3 / 8.
∞
∑4 k