计算 ∫0TWs2dWs\int_0^T W_s^2 dW_s∫0TWs2dWs Evaluate the integral 专题 Finance / 金融 难度 L4 来源 QuantQuestion 题目详情 Evaluate the integral ∫0TWs2dWs\int_{0}^{T} W_{s}^{2} d W_{s}∫0TWs2dWs 解析 对 f(x)=13x3f(x)=\tfrac13x^3f(x)=31x3 用 Itô: d(13Ws3)=Ws2dWs+Wsds.d\left(\tfrac13W_s^3\right)=W_s^2 dW_s+W_s ds.d(31Ws3)=Ws2dWs+Wsds. 又由 d(sWs)=sdWs+Wsdsd(sW_s)=s dW_s+W_s dsd(sWs)=sdWs+Wsds,得 ∫0TWsds=TWT−∫0TsdWs.\int_0^T W_s ds=T W_T-\int_0^T s dW_s.∫0TWsds=TWT−∫0TsdWs. 合并可得恒等式 ∫0TWs2dWs=WT33−TWT+∫0Ts dWs.\boxed{\int_0^T W_s^2 dW_s=\frac{W_T^3}{3}-T W_T+\int_0^T s\,dW_s}.∫0TWs2dWs=3WT3−TWT+∫0TsdWs. 其中 ∫0Ts dWs∼N(0,T33)\int_0^T s\,dW_s\sim N\left(0,\frac{T^3}{3}\right)∫0TsdWs∼N(0,3T3)。