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金价数字 call:计算 ITM 概率

Cash-or-nothing

专题
Finance / 金融
难度
L4

题目详情

Let G()G(\cdot) denote the gold price.
Now is time tt, and time TT is six months from now.

The naive (and incorrect) step is to conclude that a volatility of σ=60\sigma = 60 per annum translates to a six-month volatility of 3030.

In fact, volatility grows with the square root of the term. Thus, 6060 per year translates to about 12×6042\sqrt{\frac{1}{2}}\times 60\approx 42 per half-year.

How do we find the probability that the option finishes in-the-money, P(G(T)>430)P(G(T) > 430)?

With r=0r=0 there is no drift in the risk-neutral world, so the distribution of G(T)G(T) is centered on G(t)=400G(t)=400, with standard deviation roughly 4242.

解析

题目用近似:r=0r=0 且价格半年波动约为

σ6m=60%×1/242%.\sigma_{6m}=60\%\times\sqrt{1/2}\approx 42\%.

G(t)=400G(t)=400 为中心,标准差约 4242。所求

P(G(T)>430)=P(G(T)400>30)1Φ(3042)=1Φ(0.75).\mathbb{P}(G(T)>430)=\mathbb{P}(G(T)-400>30)\approx 1-\Phi\left(\frac{30}{42}\right) =1-\Phi(0.75).

P(G(T)>430)1Φ(0.75)0.227.\boxed{\mathbb{P}(G(T)>430)\approx 1-\Phi(0.75)\approx 0.227}.

若是现金或无数字期权(支付 1)且 r=0r=0,价格就等于该概率。