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布朗运动在 y=ty=t 上方停留的期望总时长

Expected total time

专题
Finance / 金融
难度
L4

题目详情

What is the expected total time that the Brownian motion {Bt}0t<+\{B_{t}\}_{0\leq t< +\infty} spends above the line y=ty = t ?

解析

要求

E=E[01{Bs>s}ds].E=\mathbb{E}\left[\int_0^{\infty}\mathbf{1}_{\{B_s>s\}}\,ds\right].

由 Fubini:

E=0P(Bs>s)ds.E=\int_0^{\infty}\mathbb{P}(B_s>s)\,ds.

Bs=sZB_s=\sqrt{s}\,ZZN(0,1)Z\sim N(0,1),则

P(Bs>s)=P(Z>s).\mathbb{P}(B_s>s)=\mathbb{P}(Z>\sqrt{s}).

因此

E=0P(Z>s)ds=E[(Z+)2]=12.E=\int_0^{\infty}\mathbb{P}(Z>\sqrt{s})\,ds=\mathbb{E}\left[(Z^+)^2\right]=\frac{1}{2}.

E=12.\boxed{E=\frac12}.