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两独立 U(0,1):XY>1/2XY>1/2 概率

乘积大于 1/2

专题
Probability / 概率
难度
L4

题目详情

Suppose we draw two random numbers XX and YY each distributed uniform on the interval [0,1][0, 1] . If XX and YY are independent, what is the probability that their product is greater than 1/21 / 2 ?

解析

在单位正方形上积分。条件 XY>1/2XY>1/2 等价于 y>frac12xy>\\frac{1}{2x}xge1/2x\\ge 1/2。\n\n面积为\n\n\nint1/21left(1frac12xright)dx=left[xfrac12lnxright]1/21=frac12(1ln2).\n\n\\int_{1/2}^{1}\\left(1-\\frac{1}{2x}\\right)dx=\\left[x-\\frac{1}{2}\\ln x\\right]_{1/2}^{1}=\\frac{1}{2}(1-\\ln 2).\n\n\n因此\n\n\nboxedmathbbP(XY>1/2)=frac12(1ln2)approx0.1534.\n\n\\boxed{\\mathbb{P}(XY>1/2)=\\frac{1}{2}(1-\\ln 2)\\approx 0.1534}.\n