HMMT 十一月 2012 · 团队赛 · 第 10 题
HMMT November 2012 — Team Round — Problem 10
题目详情
英文原题
- [ 6 ] Triangle ABC has AB = 4, BC = 5, and CA = 6. Points A , B , C are such that B C is tangent
′ ′ ′ ′
to the circumcircle of △ ABC at A , C A is tangent to the circumcircle at B , and A B is tangent to
′ ′
the circumcircle at C . Find the length B C .
解析
英文解析
- [ 6 ] Triangle ABC has AB = 4, BC = 5, and CA = 6. Points A , B , C are such that B C is tangent
′ ′ ′ ′
to the circumcircle of △ ABC at A , C A is tangent to the circumcircle at B , and A B is tangent to
′ ′
the circumcircle at C . Find the length B C .
′ ′ ′ ′ ′ ′80
Answer: Note that by equal tangents, B A = B C , C A = C B , and A B = A C . Moreover,
′ ′ ′ ′ ′ ′3
since the line segments A B , B C , and C A are tangent to the circumcircle of ABC at C , A , and
′ ′ ′ ′ ′
B respectively, we have that ∠ A BC = ∠ A CB = ∠ A , ∠ B AC = ∠ B CA = ∠ B , and ∠ C BA =
′ ′ ′
∠ C AB = ∠ C . By drawing the altitudes of the isosceles triangles BC A and AC B , we therefore have
′ ′
that C A = 2 / cos C and B A = 3 / cos B .
Now, by the Law of Cosines, we have that
2 2 2
a + c − b 25 + 16 − 36 1
cos B = = =
2 ac 2(5)(4) 8
2 2 2
a + b − c 25 + 36 − 16 3
cos C = = = .
2 ab 2(5)(6) 4
Therefore,
( )
4 80
′ ′ ′ ′
B C = C A + B A = 2 + 3(8) = .
3 3
Team Round