HMMT 二月 2012 · 冲刺赛 · 第 12 题
HMMT February 2012 — Guts Round — Problem 12
题目详情
- [ 5 ] Knot is ready to face Gammadorf in a card game. In this game, there is a deck with twenty cardsnumbered from 1 to 20. Each player starts with a five card hand drawn from this deck. In each round,
Gammadorf plays a card in his hand, then Knot plays a card in his hand. Whoever played a cardwith greater value gets a point. At the end of five rounds, the player with the most points wins. If
Gammadorf starts with a hand of 1 , 5 , 10 , 15 , 20, how many five-card hands of the fifteen remainingcards can Knot draw which always let Knot win (assuming he plays optimally)?
15 ANNUAL HARVARD-MIT MATHEMATICS TOURNAMENT, 11 FEBRUARY 2012 — GUTS ROUNDTH
英文原题
[5]
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15 TH ANNUAL HARVARD-MIT MATHEMATICS TOURNAMENT, 11 FEBRUARY 2012— GUTS ROUND
School Team Team ID#
解析
英文解析
- [ 5 ] Knot is ready to face Gammadorf in a card game. In this game, there is a deck with twenty cardsnumbered from 1 to 20. Each player starts with a five card hand drawn from this deck. In each round,
Gammadorf plays a card in his hand, then Knot plays a card in his hand. Whoever played a cardwith greater value gets a point. At the end of five rounds, the player with the most points wins. If
Gammadorf starts with a hand of 1 , 5 , 10 , 15 , 20, how many five-card hands of the fifteen remainingcards can Knot draw which always let Knot win (assuming he plays optimally)?
Answer: 2982 Knot can only lose if all of his cards are lower than 10; if not he can win by playingthe lowest card that beats Gammadorf’s card, or if this is not possible, his lowest card, each turn.
( ) ( ) ( )
7 15 7
There are = 21 losing hands, so he has − possible winning hands.
5 5 5