HMMT 十一月 2009 · GEN1 赛 · 第 2 题
HMMT November 2009 — GEN1 Round — Problem 2
题目详情
英文原题
- [ 3 ] Given that a + b + c = 5 and that 1 ≤ a, b, c ≤ 2, what is the minimum possible value of + ?
a + b b + c
解析
英文解析
- [ 3 ] Given that a + b + c = 5 and that 1 ≤ a, b, c ≤ 2, what is the minimum possible value of + ?
a + b b + c
Answer: If a > 1 and b < 2, we can decrease the sum by decreasing a and increasing b . You can 4
follow a similar procedure if c > 1 and b < 2. Therefore, the sum is minimized when b = 2. We can 7
a + c +4 7
then cross-multiply the two fractions and see that we are trying to minimize = .
( a +2)( c +2) ( a +2)( c +2)
The product of two numbers with a fixed sum is maximized when those two numbers are equal, so
7 3 4
is minimized for a = c = , which gives us an answer of .
( a +2)( c +2) 2 7