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HMMT 十一月 2009 · GEN1 赛 · 第 2 题

HMMT November 2009 — GEN1 Round — Problem 2

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 3 ] Given that a + b + c = 5 and that 1 ≤ a, b, c ≤ 2, what is the minimum possible value of + ?
    a + b b + c
解析

英文解析

  1. [ 3 ] Given that a + b + c = 5 and that 1 ≤ a, b, c ≤ 2, what is the minimum possible value of + ?
    a + b b + c
    Answer: If a > 1 and b < 2, we can decrease the sum by decreasing a and increasing b . You can 4
    follow a similar procedure if c > 1 and b < 2. Therefore, the sum is minimized when b = 2. We can 7
    a + c +4 7
    then cross-multiply the two fractions and see that we are trying to minimize = .
    ( a +2)( c +2) ( a +2)( c +2)
    The product of two numbers with a fixed sum is maximized when those two numbers are equal, so
    7 3 4
    is minimized for a = c = , which gives us an answer of .
    ( a +2)( c +2) 2 7