HMMT 二月 2009 · 代数 · 第 7 题
HMMT February 2009 — Algebra — Problem 7
题目详情
英文原题
- [ 5 ] Simplify the product
100 100
n + m n + m +2 2 n +1 2 m +1
∏ ∏
x + x + x + x
.
2 n n + m 2 mx + 2 x + xm =1 n =1
Express your answer in terms of x .
2 2 3 3
解析
英文解析
- [ 5 ] Simplify the product
100 100
n + m n + m +2 2 n +1 2 m +1
∏ ∏
x + x + x + x
.
2 n n + m 2 mx + 2 x + xm =1 n =1
Express your answer in terms of x .
( )
1002
1+ x 1 1 1
9900 9900 10000 10100
Answer: x (OR x + x + x )
2 4 2 4
Solution: We notice that the numerator and denominator of each term factors, so the product isequal to
100 100
m n +1 m +1 n
∏ ∏
( x + x )( x + x )
.
m n 2
( x + x )
m =1 n =1
Each term of the numerator cancels with a term of the denominator except for those of the formm 101 101 n
( x + x ) and ( x + x ) for m, n = 1 , . . . , 100, and the terms in the denominator which remain are
1 n 1 mof the form ( x + x ) and ( x + x ) for m, n = 1 , . . . , 100. Thus the product simplifies to
( )
1002
m 101
∏
x + x
1 mx + xm =1
Reversing the order of the factors of the numerator, we find this is equal to
( ) ( )
2 2
100 100
101 − m 101 1 m +1
∏ ∏
x + x x + x
100 − m = x
1 m 1 mx + x x + xm =1 m =1
( )
1002
1 1
∏
x + x 01
100 − m = x
1 1
x + xm =1
( )
1002
99 · 100 1 + x = ( x )22
as desired.2
2 2 3 3