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HMMT 二月 2009 · 代数 · 第 6 题

HMMT February 2009 — Algebra — Problem 6

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 5 ] Let x and y be positive real numbers and θ an angle such that θ 6 = n for any integer n . Supposesin θ cos θ2
    x y=
    4 andcos θ sin θ 97 sin 2 θ4 + = .
    4 4 3 3
    x y x y + y xy
    Compute + .xy x
解析

英文解析

  1. [ 5 ] Let x and y be positive real numbers and θ an angle such that θ 6 = n for any integer n . Supposesin θ cos θ2
    x y=
    4 andcos θ sin θ 97 sin 2 θ4 + = .
    4 4 3 3
    x y x y + y xy 1
    Compute + .xy x
    Answer: 4
    Solution: From the first relation, there exists a real number k such that x = k sin θ and y = k cos θ .
    Then we havecos θ sin θ 194 sin θ cos θ44 + = = 194 .
    4 2
    cos θ24
    sin θ sin θ cos θ (cos θ + sin θ )
    4 4
    x 2 2 cos θ sin θy
    Notice that if t = + then ( t − 2) − 2 = + = 194 and so t = 4.
    y x sin θ cos θ44