HMMT 二月 2008 · TEAM2 赛 · 第 12 题
HMMT February 2008 — TEAM2 Round — Problem 12
题目详情
英文原题
- [ 35 ] Show that the incenter of triangle AEF lies on the incircle of ABC .
解析
英文解析
- [ 35 ] Show that the incenter of triangle AEF lies on the incircle of ABC .
Solution: Let segment AI meet the incircle at A . Let us show that A is the incenter of
1 1
AEF .
A5
1A
B CIEF
′D
Since AE = AF and AA is the angle bisector of ∠ EAF , we find that A E = A F . Using
1 1
tangent-chord, we see that ∠ AF A = ∠ A EF = ∠ A F E . Therefore, A lies on the angle
1 1 1 1
bisector of ∠ AF E . Since A also lies on the angle bisector of ∠ EAF , A must be the incenter
1 1
of AEF , as desired.