HMMT 二月 2008 · TEAM2 赛 · 第 11 题
HMMT February 2008 — TEAM2 Round — Problem 11
题目详情
英文原题
- [ 15 ] Show that lines AD, BE, CF pass through a common point.
解析
英文解析
- [ 15 ] Show that lines AD, BE, CF pass through a common point.
Solution: Using Ceva’s theorem on triangle ABC , we see that it suffices to show that
BD CE AF
· · = 1 .
DC EA F B
Since AF = AE , BD = BF , and CD = CE (due to equal tangents), we see that the LHS isindeed 1.
Remark: The point of concurrency is known as the Gergonne point .