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HMMT 二月 2007 · COMB 赛 · 第 1 题

HMMT February 2007 — COMB Round — Problem 1

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 3 ] A committee of 5 is to be chosen from a group of 9 people. How many ways can it be chosen, if
    Biff and Jacob must serve together or not at all, and Alice and Jane refuse to serve with each other?
解析

英文解析

  1. [ 3 ] A committee of 5 is to be chosen from a group of 9 people. How many ways can it be chosen, if
    Biff and Jacob must serve together or not at all, and Alice and Jane refuse to serve with each other?
    ( )
    Answer: 41 . If Biff and Jacob are on the committee, there are = 35 ways for the other members 7
    ( )3
    to be chosen. Amongst these 35 possibilities, we reject the = 5 choices where both Alice and Jane 5
    ( )1
    are also serving. If Biff and Jacob are not serving, then there are = 21 ways to choose the remaining 7
    ( )5
    5 members. Again, we reject the = 10 instances where Alice and Jane are chosen, so the total is 5
    (35 − 5) + (21 − 10) = 41.3