HMMT 二月 2005 · CALC 赛 · 第 7 题
HMMT February 2005 — CALC Round — Problem 7
题目详情
英文原题
- Two ants, one starting at ( − 1 , 1), the other at (1 , 1), walk to the right along the parabola y = x such that their midpoint moves along the line y = 1 with constant 2
speed 1. When the left ant first hits the line y = , what is its speed?1 2
解析
英文解析
- Two ants, one starting at ( − 1 , 1), the other at (1 , 1), walk to the right along the parabola y = x such that their midpoint moves along the line y = 1 with constant 2
speed 1. When the left ant first hits the line y = , what is its speed?1
√2
Solution: 3 3 − 3
1 3
When the left ant first hits the line y = , the right ant hits the line y = . The
2 2
√ √
2 1 6 3
left ant is then at ( − , ), and the right ant is at ( , ). Let the left ant have
2 2 2 2
velocity with components v and v , the right ant velocity with components w andx y x
√ √
v wdyy yw . Since = 2 x , = − 2 and = 6. Since the midpoint of the ants movesdx v wyx x
1 1
at speed 1 along the line y = 1, ( v + w ) = 1 and ( v + w ) = 0. Therefore,
x x y y
2 2
√
√ √ √ √
2 6
√ √
2 v = − v = w = 6 w = 6(2 − v ). Solving for v gives = 3 − 3. Thenx y y x x x
6+ 2
the speed of the left ant is
√
√
√ √ √
2 2 2 2
v + v = v + ( − 2 v ) = 3 | v | = 3 3 − 3 .
x xx y x