HMMT 二月 2005 · CALC 赛 · 第 6 题
HMMT February 2005 — CALC Round — Problem 6
题目详情
英文原题
- The graph of r = 2 + cos 2 θ and its reflection over the line y = x bound five regions inthe plane. Find the area of the region containing the origin.
解析
英文解析
- The graph of r = 2 + cos 2 θ and its reflection over the line y = x bound five regions inthe plane. Find the area of the region containing the origin.
Solution: 9 π/ 2 − 8
π 3 π 5 π 7 π
The original graph is closer to the origin than its reflection for θ ∈ ( , ) ∪ ( , ),
4 4 4 4
and the region is symmetric about the origin. Therefore the area we wish to find isthe polar integral
3 π 3 π
∫ ∫
4 1 4
2 2
4 (2 + cos 2 θ ) dθ = 2 (4 + 4 cos 2 θ + cos 2 θ ) dθπ π
4 42
( )
∫ 3 π = 2 4 + 4 cos 2 θ + (1 + cos 4 θ ) dθ41
2π
3 π4
[ ] = 9 θ + 4 sin 2 θ + sin 4 θ14
4π
( ) ( )4
27 π 9 π 9 π = − 4 − + 4 = − 8 .
4 4 2 2