HMMT 二月 2004 · CALC 赛 · 第 9 题
HMMT February 2004 — CALC Round — Problem 9
题目详情
英文原题
- Find the positive constant c such that the series
∞0
∑
n !
( cn )nn =0
converges for c > c and diverges for 0 < c < c .
0 0
3 3 2 1 [1] [ n +1]
解析
英文解析
- Find the positive constant c such that the series
∞0
∑
n !
( cn )nn =0
converges for c > c and diverges for 0 < c < c .
0 0
Solution: 1 /e
The ratio test tells us that the series converges if
( )
n +1
( n + 1)! / ( c ( n + 1)) 1 nnlim = · limn →∞ n →∞nn ! / ( cn ) c n + 1
is less than one and diverges if it is greater than one. But
( ) ( ) − nnn 1 1
lim = lim 1 + = .
n →∞ n →∞
n + 1 n e
Then the limit above is just 1 /ce , so the series converges for c > 1 /e and diverges for
0 < c < 1 /e .
3 1
3 2 [1] [ n +1]