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HMMT 二月 2004 · CALC 赛 · 第 8 题

HMMT February 2004 — CALC Round — Problem 8

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. If x and y are real numbers with ( x + y ) = x − y , what is the maximum possible valueof y ?
解析

英文解析

  1. If x and y are real numbers with ( x + y ) = x − y , what is the maximum possible valueof y ?

    Solution: 3 2 / 163
    °2
    By drawing the graph of the curve (as shown), which is just a 135 clockwise rotationand scaling of y = x , we see that the maximum is achieved at the unique point where 4
    dy/dx = 0. Implicit differentiation gives 4( dy/dx + 1)( x + y ) = 1 − dy/dx , so setting 3
    √ √ √
    3 3 3
    3 4
    dy/dx = 0 gives 4( x + y ) = 1. So x + y = 1 / 4 = 2 / 2, and x − y = ( x + y ) = 2 / 8.
    √ √ √
    3 3 3
    Subtracting and dividing by 2 gives y = ( 2 / 2 − 2 / 8) / 2 = 3 2 / 16 .
    0.5 1 1.5
    -0.5
    -1
    -1.5