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HMMT 二月 2003 · 冲刺赛 · 第 3 题

HMMT February 2003 — Guts Round — Problem 3

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [5] If a and b are positive integers that can each be written as a sum of two squares,
    then ab is also a sum of two squares. Find the smallest positive integer c such that
    3 3 3 3
    c = ab , where a = x + y and b = x + y each have solutions in integers ( x, y ), but
    3 3
    c = x + y does not.
    HARVARD-MIT MATHEMATICS TOURNAMENT, MARCH 15, 2003 — GUTS ROUND
    1 2 3
解析

英文解析

  1. If a and b are positive integers that can each be written as a sum of two squares, thenab is also a sum of two squares. Find the smallest positive integer c such that c = ab ,
    3 3 3 3 3 3
    where a = x + y and b = x + y each have solutions in integers ( x, y ), but c = x + ydoes not.
    Solution: 4
    3 3 3 3
    We can’t have c = 1 = 1 + 0 or c = 2 = 1 + 1 , and if c = 3, then a or b = ± 3 whichis not a sum of two cubes (otherwise, flipping signs of x and y if necessary, we wouldget either a sum of two nonnegative cubes to equal 3, which clearly does not happen,
    or a difference of two nonnegative cubes to equal 3, but the smallest difference between
    3 3
    two successive cubes ≥ 1 is 2 − 1 = 7). However, c = 4 does meet the conditions,
    3 3
    with a = b = 2 = 1 + 1 (an argument similar to the above shows that there are no
    3 3
    x, y with 4 = x + y ), so 4 is the answer.
    1 2 3