HMMT 二月 2003 · 代数 · 第 6 题
HMMT February 2003 — Algebra — Problem 6
题目详情
英文原题
- Let a = 1, and let a = b n /a c for n > 1. Determine the value of a .
1 n n − 1 999
3 2 3 3 3
解析
英文解析
- Let a = 1, and let a = b n /a c for n > 1. Determine the value of a .
1 n n − 1 999
Solution: 999
We claim that for any odd n , a = n . The proof is by induction. To get the basen
3 3
cases n = 1 , 3, we compute a = 1, a = b 2 / 1 c = 8, a = b 3 / 8 c = 3. And if
1 2 3
3 2
the claim holds for odd n ≥ 3, then a = b ( n + 1) /n c = n + 3 n + 3, so a =
n +1 n +2
n +3 n +22
3 2 3 2 2
b ( n +2) / ( n +3 n +3) c = b ( n +6 n +12 n +8) / ( n +3 n +2) c = b n +2+ c = n +2.
n +3 n +32
So the claim holds, and in particular, a = 999.
3 2 3 3 3999