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HMMT 二月 2001 · 冲刺赛 · 第 9 题

HMMT February 2001 — Guts Round — Problem 9

专题
Discrete Math / 离散数学
难度
L3
来源
HMMT

题目详情

  1. [5] Suppose x satisfies x + x + x + 1 = 0. What are all possible values of x + 2 x + 2 2 x + 2 x + 1?
解析
  1. [5] Suppose x satisfies x + x + x + 1 = 0. What are all possible values of x + 2 x + 2 2 x + 2 x + 1? 4 3 2 3 2 Solution: x + 2 x + 2 x + 2 x + 1 = ( x + 1)( x + x + x + 1) = 0 is the only possible solution.