HMMT 二月 2001 · ADV 赛 · 第 2 题
HMMT February 2001 — ADV Round — Problem 2
题目详情
- Find log log · · · log in terms of n . n n − 1 2 2 3 n 27 2 2001
解析
- Find log log · · · log in terms of n . n n − 1 2 2 3 n log a 1 Solution: Using log = − log x and log a = , we get that the product equals b x log b ( − log 2)( − log 3) ··· ( − log n ) n − 1 = ( − 1) . log n ··· log 3 log 2 27 2 2001