HMMT 二月 2000 · 团队赛 · 第 15 题
HMMT February 2000 — Team Round — Problem 15
题目详情
英文原题
- lim nr 1 os =?
n !1 n
解析
英文解析
- Consider a regular n -gon with radius r . Let x be the side length of the n -gon. So,
sin e the en tral angle is (see diagram b elo w), use the La w of Cosines to nd that 2
2 2 2 2 2 2 2 2 pqnx = r + r 2 r r os , so x = 2 r (1 os ). Th us, x = r 2 1 os .
n n nq
2 p
So, the total p erimeter of the n -gon is nx = nr 2 1 os . No w, if we tak enlim of the p erimeter, the result will be 2 n , sin e the n -gon approa hes a irle,
n !1
q qp pso lim nr 2 1 os = 2 r , and so lim nr 1 os = r 2 .22
n !1 n !1
rxnnr
2 πn