HMMT 二月 2000 · 代数 · 第 1 题
HMMT February 2000 — Algebra — Problem 1
题目详情
- Ho w man y in tegers x satisfy j x j + 5 < 7 and j x 3 j > 2? 3 2 2 3
解析
- The only in tegers that satisfy j x j + 5 < 7 are the ones that satisfy j x j < 2 - namely , 1 ; 0 ; 1. The in tegers that satisfy j x 3 j > 2 are 6 ; 7 ; 8 ; : : : and 0 ; 1 ; 2 ; : : : . So, the in tegers that satisfy b oth are 0 ; 1, and there are 2 of them. 3 2 2 3 2