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正方形桌面覆盖至少 3 只蚂蚁

Ants on a Square

专题
Brainteaser / 脑筋急转弯
难度
L4

题目详情

边长为 1 的正方形桌面上有 51 只蚂蚁。你有一个半径为 1/71/7 的圆形玻璃杯。

证明:总能把杯子放在某个位置,使其覆盖至少 3 只蚂蚁。

There is a 1×1 square with 51 ants on it. You have a circular glass of radius 1/7. Show that you can place the glass in a position so that it covers at least 3 ants.

解析

用抽屉原理。

把正方形划分成足够多的小区域,使得每个小区域都能被半径 1/71/7 的圆覆盖(例如划成边长不超过 2/72/7 的小正方形网格)。

这些小区域数量有限。51 只蚂蚁落入这些区域中,根据抽屉原理,至少有一个区域包含至少 3 只蚂蚁。

把杯子覆盖该区域即可覆盖至少 3 只。


Original Explanation

Divide the square into a grid of small squares (or use pigeonhole). A suitable approach is to show that you can partition so that at least one subregion must have 3 or more ants. Then note that a circle of radius 1/7 can cover that subregion. One can do a more precise argument involving (1/5)(1/5)-sized squares, or an equivalent geometric argument, ensuring at least 3 ants are within the circle.