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涂红 10×20×30:随机小块红面数期望

Better in Red II

专题
Probability / 概率
难度
L4

题目详情

一个 10×20×30 的长方体外表面全部涂成红色,然后切成 6000 个 1×1×1 小立方体。随机均匀选取一个小立方体。

问:该小立方体红色面的期望数量是多少?

A 10×20×3010 \times 20 \times 30 rectangular prism is painted red on the surface and then cut into 60006000 1×1×11 \times 1 \times 1 cubes and one is selected uniformly at random. Find the expected number of red faces on this cube.

解析

总红色小面数等于长方体表面积:

2(1020+2030+1030)=2(200+600+300)=2200.2(10\cdot 20+20\cdot 30+10\cdot 30)=2(200+600+300)=2200.

共有 6000 个小立方体,因此随机小立方体红面数期望为

22006000=1130.\frac{2200}{6000}=\frac{11}{30}.

Original Explanation

Label the faces of each cube 161-6, and then let IiI_i be the indicator that side ii of the cube that is drawn is colored red. Then T=I1++I6T = I_1 + \dots + I_6 gives the total number of red sides of the cube. We need to be careful here, as the indicators are not exchangeable. Instead, two of the indicators will correspond to a 10×2010 \times 20 side, two to a 20×3020 \times 30 side, and two to a 10×3010 \times 30 side. Therefore, there are 3 subsets of indicators that are exchangeable, so we can reduce it to an expectation involving 3 indicators and multiply it by 2, so E[T]=2(E[I1]+E[I2]+E[I3])\mathbb{E}[T] = 2(\mathbb{E}[I_1] + \mathbb{E}[I_2] + \mathbb{E}[I_3]), where we take I1I_1 to indicate a 10×2010 \times 20 side, I2I_2 to indicate a 20×3020 \times 30 side, and I3I_3 to indicate a 10×3010 \times 30 side.

Then, to evaluate these expectations, we just need to find the probability that the side indicated is red on our cube. For I1I_1, that is 1020=20010 \cdot 20 = 200 cubes. For I2I_2, that is 2030=60020 \cdot 30 = 600 cubes. For I3I_3, that is 1030=30010 \cdot 30 = 300 cubes. All of these need to be divided by 60006000 as that is the volume of the entire prism. Therefore, E[T]=2(200+300+600)6000=1130\mathbb{E}[T] = \dfrac{2(200 + 300 + 600)}{6000} = \dfrac{11}{30}.