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轮盘+对赌:最终期望收益

Curing the Gambler

专题
Strategy / 策略
难度
L4

题目详情

量化面试题:轮盘+对赌:最终期望收益。

英文原题

Mr. Brown always bets a dollar on the number 13 at roulette against the advice of Kind Friend. To help cure Mr. Brown of playing roulette, Kind Friend always bets Brown $20 at even money that Brown will be behind at the end of 36 plays. How is the cure working?

(Most American roulette wheels have 38 equally likely numbers. If the player's number comes up, he is paid 35 times his stake and gets his original stake back; otherwise he loses his stake.)

解析

36 次押单号 13:一次期望为\n\n\n35cdotfrac1381cdotfrac3738=frac238.\n\n35\\cdot\\frac{1}{38}-1\\cdot\\frac{37}{38}=-\\frac{2}{38}.\n\n\n36 次期望为 36cdot(2/38)=72/38approx1.8936\\cdot(-2/38)=-72/38\\approx -1.89。\n\n若 36 次内从未命中 13,则总收益为 -36,概率为 (37/38)36approx0.383(37/38)^{36}\\approx 0.383。朋友押“最终为负”,其对赌期望为\n\n\n20cdot(10.383)20cdot0.383approx+4.68.\n\n20\\cdot(1-0.383)-20\\cdot 0.383\\approx +4.68.\n\n\n合并期望约为 4.681.89approxboxed+2.794.68-1.89\\approx \\boxed{+2.79}


英文解析

If Mr. Brown wins once in 36 turns, he is even with the casino. His probability of losing all 36 times is (3738)360.383\left(\frac{37}{38}\right)^{36} \approx 0.383 . In a single turn his expectation

is

35(138)1(3738)=238(dollars),35\left(\frac{1}{38}\right) - 1\left(\frac{37}{38}\right) = -\frac{2}{38} (\mathrm{dollars}),

and in 36 turns

2(36)381.89(dollars)-\frac{2(36)}{38}\approx -1.89 (\mathrm{dollars})

Against Kind Friend, Mr. Brown has an expectation of

+20(0.617)20(0.383)+4.68(dollars).+20(0.617) - 20(0.383)\approx +4.68 (\mathrm{dollars}).

And so all told Mr. Brown gains +4.681.89=+2.79+4.68 - 1.89 = +2.79 dollars per 36 trials; he is finally making money at roulette. Possibly Kind Friend will be cured first. Of course, when Brown loses all 36, he is out 5656, which may jolt him a bit.