地球有多重

严格来说，“重量”取决于所处引力场；更常见、也更物理的量是地球的质量。

地球质量约为

$$M_\oplus\approx 5.97\times 10^{24}\ \text{kg}.$$

若把“重量”理解为在地表重力加速度 $g\approx 9.81\ \text{m/s}^2$ 下对应的重力大小，则

$$W\approx M_\oplus g\approx 5.97\times 10^{24}\times 9.81\approx 5.86\times 10^{25}\ \text{N}.$$

所以可回答：质量约 $6\times 10^{24}$ kg，地表重量数量级约 $6\times 10^{25}$ N。

---

英文解析

Strictly speaking, "weight" depends on the gravitational field in which one is located; the more common and physically accurate quantity is Earth's mass.

Earth's mass is approximately

$$M_\oplus\approx 5.97\times 10^{24}\ \text{kg}.$$

If "weight" is understood as the magnitude of the gravitational force corresponding to the surface gravity $g\approx 9.81\ \text{m/s}^2$, then

$$W\approx M_\oplus g\approx 5.97\times 10^{24}\times 9.81\approx 5.86\times 10^{25}\ \text{N}.$$

Thus, one can answer: the mass is approximately $6\times 10^{24}$ kg, and the order of magnitude of the weight at the surface is approximately $6\times 10^{25}$ N.