PUMaC 2022 · 个人决赛(A 组) · 第 1 题
PUMaC 2022 — Individual Finals (Division A) — Problem 1
题目详情
- Let f : Z → Z be a function which satisfies k | f ( x ) − x for all k, x ∈ Z and f ( x ) − x ≤
0 > 0 > 0
- If f (1) = 2000, what can f be? k Remark: Here, f ( x ) denotes the k -fold application of f to x .
解析
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Original Explanation
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