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PUMaC 2021 · 数论(B 组) · 第 57 题

PUMaC 2021 — Number Theory (Division B) — Problem 57

专题
Discrete Math / 离散数学
难度
L3
来源
PUMaC

题目详情

Number Theory B

  1. Andrew has a four-digit number whose last digit is 2. Given that this number is divisible by 9 , determine the number of possible values for this number that Andrew could have. Note that leading zeros are not allowed.
  2. The smallest three positive proper divisors of an integer n are d < d < d and they satisfy 1 2 3 d + d + d = 57 . Find the sum of the possible values of d . 1 2 3 2 5 2 3 3 5 2
  3. Compute the remainder when 2 + 3 + 5 is divided by 30.
  4. A substring of a number n is a number formed by removing some digits from the beginning and end of n (possibly a different number of digits is removed from each side). Find the sum of all prime numbers p that have the property that any substring of p is also prime.
  5. Compute the number of ordered pairs of non-negative integers ( x, y ) which satisfy 2 2 x + y = 32045 . P e e e 3 1 2 k
  6. Let f ( n ) = k . If the prime factorization of f (2020) can be written as p p . . . p , 1 2 k gcd( k,n )=1 , 1 ≤ k ≤ n k P find p e . i i i =1
  7. Suppose that f : Z × Z → R , satisfies the equation f ( x, y ) = f (3 x + y, 2 x + 2 y ) for all x, y ∈ Z . Determine the maximal number of distinct values of f ( x, y ) for 1 ≤ x, y ≤ 100 . P n gcd( i,n )
  8. Let f ( n ) = . Find the sum of all positive integers n for which f ( n ) = 6 . i =1 n 1
解析

57 . Find the sum of the possible values of d . 2 Proposed by: Frank Lu Answer: 42 Note that d = 1 for all n . It suffices to solve d + d = 56. 1 2 3 Note that the only possibilities that we have for d , d are either that d , d are distinct primes, 2 3 2 3 2 or that d is equal to d , where d is a prime. For the second, notice that there is only one 3 2 2 2 possible solution, namely by d + d = 56 , yielding us with d = 7 . 2 2 2 In the other case, we see that we want d , 56 − d to both be primes. We see that the primes less 2 2 than 28 are 2 , 3 , 5 , 7 , 11 , 13 , 17 , 19 , 23 , with 56 − d equaling, respectively, 54 , 53 , 51 , 49 , 45 , 43 , 39 , 37 , 33 . 2 But from this list, the only pairs that work are (3 , 53) , (13 , 43) , and (19 , 37) . Therefore, it fol- lows that the sum of the possible d is 3 + 7 + 13 + 19 = 42 . 2 5 2 3 3 5 2