PUMaC 2021 · 数论(B 组) · 第 2 题
PUMaC 2021 — Number Theory (Division B) — Problem 2
题目详情
- The smallest three positive proper divisors of an integer n are d < d < d and they satisfy 1 2 3 d + d + d = 57 . Find the sum of the possible values of d . 1 2 3 2 5 2 3 3 5 2
解析
- The smallest three positive proper divisors of an integer n are d < d < d so that d + d + d = 1 2 3 1 2 3