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PUMaC 2020 · 团队赛 · 第 5 题

PUMaC 2020 — Team Round — Problem 5

专题
Discrete Math / 离散数学
难度
L3
来源
PUMaC

题目详情

  1. Suppose two polygons may be glued together at an edge if and only if corresponding edges of the same length are made to coincide. A 3 × 4 rectangle is cut into n pieces by making straight line cuts. What is the minimum value of n so that it’s possible to cut the pieces in such a way that they may be glued together two at a time into a polygon with perimeter at least 2021?
解析
  1. Suppose two polygons may be glued together at an edge if and only if corresponding edges of the same length are made to coincide. A 3 × 4 rectangle is cut into n pieces by making straight line cuts. What is the minimum value of n so that it’s possible to cut the pieces in such a way that they may be glued together two at a time into a polygon with perimeter at least 2021? Proposed by: Austen Mazenko Answer: 202 For n pieces, edges must be glued together at least n − 1 times, and each gluing event reduces the overall perimeter by twice the length of the edges being glued together. Furthermore, every time a cut is made to divide the bar into more pieces, it increases the total perimeter by at most twice the length of the largest cut, which is 5 (the length of the rectangle’s diagonal). To form n pieces, there are at most n − 1 cuts. Hence, an upper bound for the perimeter is 3 + 4 + 3 + 4 + 2 · 5 · ( n − 1) − 2 · 0 · ( n − 1) = 10 n + 4 since every edge being glued together has a length > 0 and all cuts have length ≤ 5. Accordingly, we need 10 n + 4 ≥ 2021 = ⇒ n ≥ 202 since n must be an integer. To see that n = 202 is sufficient, put the bar on the coordinate i plane so that it has one vertex on the origin and one at (4 , 3). First, make 200 cuts from ( , 0) N i to (4 , 3 − ) for 1 ≤ i ≤ 200 and some large integer N . N Finally, cut the bottom right triangle like so: 1 N 1 N 1 Now, all of the thin strips have two edges of length , so they may be glued together in N sequence like so: 3 √ ( ) ( ) 2 2 201 201 1 By Pythagorean Theorem, each cut has length at least 3 − + 4 − − . Making N N N N arbitrarily large, each cut may have a length sufficiently close to 5 and each small edge may have sufficiently small length so that the perimeter will exceed 2021, as desired.