PUMaC 2016 · 数论（A 组） · 第 1 题
PUMaC 2016 — Number Theory (Division A) — Problem 1
题目详情
- What is the smallest positive integer n such that 2016 n is a perfect cube?
解析
- 2016 = 2 · 3 · 7, so to get a cube we multiply it by 2 · 3 · 7 = 294 . Problem written by Eric Neyman.