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PUMaC 2014 · 团队赛 · 第 8 题

PUMaC 2014 — Team Round — Problem 8

专题
Discrete Math / 离散数学
难度
L3
来源
PUMaC

题目详情

  1. [ 7 ] Let n 6 n + 1 = 0. Find n + 6 n r q p p
解析
  1. [ 7 ] Let n − 6 n + 1 = 0. Find n + 6 n Solution: 1 1 1 2 4 2 We see that we have n + = 6. Hence n + = 36 − 2 = 34 and n + = 34 − 2 = 1154. 2 4 n n n 1 1 1 4 2 6 Therefore we have that ( n + )( n + ) = 1154 × 34 Thus n + = 1154 × 34 − 34 = 4 2 6 n n n 1153 × 34 = 39202 . √ √ √ √