PUMaC 2013 · 几何（B 组） · 第 4 题
PUMaC 2013 — Geometry (Division B) — Problem 4
题目详情
- [ 4 ] An equilateral triangle is given. A point lies on the incircle of the triangle. The smallest two distances from the point to the sides of the triangle is 1 and 4. The sidelength of this √ a b triangle can be expressed as where ( a, c ) = 1 and b is not divisible by the square of an c integer greater than 1. Find a + b + c .
解析
- [ 4 ] An equilateral triangle is given. A point lies on the incircle of the triangle. The smallest two distances from the point to the sides of the triangle is 1 and 4. The sidelength of this p a b triangle can be expressed as where ( a, c ) = 1 and b is not divisible by the square of an c integer greater than 1. Find a + b + c . Solution Same problem exists in Test A. 34