PUMaC 2010 · 几何(A 组) · 第 6 题
PUMaC 2010 — Geometry (Division A) — Problem 6
题目详情
- In the following diagram, a semicircle is folded along a chord AN and intersects its diameter 2 M N at B . Given that M B : BN = 2 : 3 and M N = 10. If AN = x , find x .
解析
- In the following diagram, a semicircle is folded along a chord AN and intersects its diameter 2 M N at B . Given that M B : BN = 2 : 3 and M N = 10. If AN = x , find x . [Answer] 80 [Solution] Let C be symmetry point of B w.r.t. AN , then C is on arc AN with CN = BN = 6. √ 2 2 Then M C = 8. Suppose AN = x , then AM = 10 − x . Also, by symmetry, AM = AC . Apply Ptolemy’s Theorem on cyclic quadrilateral AM N C we get: AM · CN + M N · AC = AN · M C √ √ 2 2 2 2 ⇒ 6 10 − x + 10 10 − x = 8 x √ Solve for x we get x = 4 5.