PUMaC 2010 · 代数(A 组) · 第 2 题
PUMaC 2010 — Algebra (Division A) — Problem 2
题目详情
- Calculate b 2010 c − 1 where b x c is the largest integer less than or equal to x . n =1 x 4
解析
- Calculate b 2010 c − 1 . n =1 10 Solution: 2077. Just calculate it; note that for n > 10 we have 2 > 2010 so all those terms are zero. We get 2009 + 43 + 11 + 5 + 3 + 2 + 1 + 1 + 1 + 1 = 2077. x 4