PUMaC 2008 · 数论（A 组） · 第 7 题
PUMaC 2008 — Number Theory (Division A) — Problem 7
题目详情
- (5 points)Find the smallest positive integer n such that 32 = 167 x + 2 for some integer x .
解析
暂无解答链接。
Original Explanation
No solutions link available.
PUMaC 2008 — Number Theory (Division A) — Problem 7
暂无解答链接。
No solutions link available.