PUMaC 2008 · 组合(A 组) · 第 5 题
PUMaC 2008 — Combinatorics (Division A) — Problem 5
题目详情
- (4 points) In how many ways can Alice, Bob, Charlie, David, and Eve split 18 marbles among themselves so that no two of them have the same number of marbles?
解析
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Original Explanation
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