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HMMT 十一月 2020 · THM 赛 · 第 2 题

HMMT November 2020 — THM Round — Problem 2

专题
Discrete Math / 离散数学
难度
L3
来源
HMMT

题目详情

  1. In the future, MIT has attracted so many students that its buildings have become skyscrapers. Ben and Jerry decide to go ziplining together. Ben starts at the top of the Green Building, and ziplines to the bottom of the Stata Center. After waiting a seconds, Jerry starts at the top of the Stata Center, and ziplines to the bottom of the Green Building. The Green Building is 160 meters tall, the Stata Center is 90 meters tall, and the two buildings are 120 meters apart. Furthermore, both zipline at 10 meters per second. Given that Ben and Jerry meet at the point where the two ziplines cross, compute 100 a .
解析
  1. In the future, MIT has attracted so many students that its buildings have become skyscrapers. Ben and Jerry decide to go ziplining together. Ben starts at the top of the Green Building, and ziplines to the bottom of the Stata Center. After waiting a seconds, Jerry starts at the top of the Stata Center, and ziplines to the bottom of the Green Building. The Green Building is 160 meters tall, the Stata Center is 90 meters tall, and the two buildings are 120 meters apart. Furthermore, both zipline at 10 meters per second. Given that Ben and Jerry meet at the point where the two ziplines cross, compute 100 a . Proposed by: Esha Bhatia Answer: 740 Solution: Define the following lengths: u v Green x y Stata z x z 4 25 Note that due to all the 3-4-5 triangles, we find = = , so 120 = x + y = z . Then, z y 3 12 5 20 16 u = x = z = 120 = 128 , 3 9 15 while 5 15 9 v = y = z = 120 = 54 . 4 16 20 Thus u − v = 74, implying that a = 7 . 4.