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HMMT 二月 2017 · 冲刺赛 · 第 9 题

HMMT February 2017 — Guts Round — Problem 9

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

英文原题

  1. [ 7 ] Jeffrey writes the numbers 1 and 100000000 = 10 on the blackboard. Every minute, if x, y are onthe board, Jeffrey replaces them with
    ( ) − 1
    x + y 1 1
    and 2 + .
    2 x y
    After 2017 minutes the two numbers are a and b . Find min( a, b ) to the nearest integer.
解析

英文解析

  1. [ 7 ] Jeffrey writes the numbers 1 and 100000000 = 10 on the blackboard. Every minute, if x, y are onthe board, Jeffrey replaces them with
    ( ) − 1
    x + y 1 1
    and 2 + .
    2 x y
    After 2017 minutes the two numbers are a and b . Find min( a, b ) to the nearest integer.
    Proposed by: Yang Liu
    Answer: 10000
    Note that the product of the integers on the board is a constant. Indeed, we have that
    ( ) − 1
    x + y 1 1
    · 2 + = xy.
    2 x y
    √
    Therefore, we expect that the answer to the problem is approximately 1 · 10 = 10 .84
    To be more rigorous, we have to show that the process indeed converges quickly enough. To show this,
    we bound the difference between the integers on the board at time i . Say that at time i , the integerson the board are a < b . Note thati i
    ( ) − 1
    a + b 1 1 ( a − b )2
    i i i id = b − a = − 2 + =
    i +1 i +1 i +1
    2 a b 2( a + b )
    i i i ib − a di i i < = .
    2 2
    The inequality at the end follows from that obvious fact that b − a < b + a . Therefore, d ≤ , soidi i i i i +1
    1082
    d < , which is extremely small. So the difference is essentially 0 at time 2017, which completes
    2017
    2017
    the argument.2