HMMT 二月 2017 · 冲刺赛 · 第 9 题
HMMT February 2017 — Guts Round — Problem 9
题目详情
英文原题
- [ 7 ] Jeffrey writes the numbers 1 and 100000000 = 10 on the blackboard. Every minute, if x, y are onthe board, Jeffrey replaces them with
( ) − 1
x + y 1 1
and 2 + .
2 x y
After 2017 minutes the two numbers are a and b . Find min( a, b ) to the nearest integer.
解析
英文解析
- [ 7 ] Jeffrey writes the numbers 1 and 100000000 = 10 on the blackboard. Every minute, if x, y are onthe board, Jeffrey replaces them with
( ) − 1
x + y 1 1
and 2 + .
2 x y
After 2017 minutes the two numbers are a and b . Find min( a, b ) to the nearest integer.
Proposed by: Yang Liu
Answer: 10000
Note that the product of the integers on the board is a constant. Indeed, we have that
( ) − 1
x + y 1 1
· 2 + = xy.
2 x y
√
Therefore, we expect that the answer to the problem is approximately 1 · 10 = 10 .84
To be more rigorous, we have to show that the process indeed converges quickly enough. To show this,
we bound the difference between the integers on the board at time i . Say that at time i , the integerson the board are a < b . Note thati i
( ) − 1
a + b 1 1 ( a − b )2
i i i id = b − a = − 2 + =
i +1 i +1 i +1
2 a b 2( a + b )
i i i ib − a di i i < = .
2 2
The inequality at the end follows from that obvious fact that b − a < b + a . Therefore, d ≤ , soidi i i i i +1
1082
d < , which is extremely small. So the difference is essentially 0 at time 2017, which completes
2017
2017
the argument.2