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HMMT 十一月 2016 · 冲刺赛 · 第 9 题

HMMT November 2016 — Guts Round — Problem 9

专题
Contest Math / 竞赛数学
难度
L3
来源
HMMT

题目详情

  1. [ 7 ] How many 3-element subsets of the set { 1 , 2 , 3 , . . . , 19 } have sum of elements divisible by 4?
    HMMT November 2016, November 12, 2016 — GUTS ROUND
    Organization Team Team ID#

英文原题

[ 7 ] How many 3-element subsets of the set { 1 , 2 , 3 , . . . , 19 } have sum of elements divisible by 4?
. . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . .
HMMT November 2016, November 12, 2016 — GUTS ROUND
Organization Team Team ID#

解析

英文解析

  1. [ 7 ] How many 3-element subsets of the set { 1 , 2 , 3 , . . . , 19 } have sum of elements divisible by 4?
    Proposed by: Sam Korsky
    Answer: 244
    Consider the elements of the sets mod 4. Then we would need to have sets of the form { 0 , 0 , 0 } ,
    { 0 , 2 , 2 } , { 0 , 1 , 3 } , { 1 , 1 , 2 } , or { 2 , 3 , 3 } . In the set { 1 , 2 , . . . , 19 } there four elements divisible by 4 and
    5 elements congruent to each of 1 , 2 , 3 mod 4. Hence the desired number is given by
    ( ) ( )( ) ( )( )( ) ( )( ) ( )( )
    4 4 5 4 5 5 5 5 5 5 + + + + = 244
    3 1 2 1 1 1 2 1 1 2