HMMT 十一月 2016 · 冲刺赛 · 第 22 题
HMMT November 2016 — Guts Round — Problem 22
题目详情
英文原题
- [ 12 ] Let the function f : Z → Z take only integer inputs and have integer outputs. For any integers xand y , f satisfiesf ( x ) + f ( y ) = f ( x + 1) + f ( y − 1)
If f (2016) = 6102 and f (6102) = 2016, what is f (1)?
解析
英文解析
- [ 12 ] Let the function f : Z → Z take only integer inputs and have integer outputs. For any integers xand y , f satisfiesf ( x ) + f ( y ) = f ( x + 1) + f ( y − 1)
If f (2016) = 6102 and f (6102) = 2016, what is f (1)?
Proposed by: Henrik Boecken
Answer: 8117
We havef ( x + 1) = f ( x ) + f ( y ) − f ( y − 1)
If y is fixed, we havef ( x + 1) = f ( x ) + constantimplying f is linear. Using our two points, then, we get f ( x ) = 8118 − x , so f (1) = 8117